Exercise · ZW-PARTIAL-DERIVATIVE-009 · ★★★ Advanced

For \(f(x,y)=|x|+y\), which statement is true at the origin?

Choose one option.

Show answer
  • B. \(f_x(0,0)\) does not exist and \(f_y(0,0)=1\)

Explanation

With \(y=0\) fixed, \(f(x,0)=|x|\) has a corner at \(x=0\): the one-sided limits of the quotient are \(1\) and \(-1\), so \(f_x(0,0)\) does not exist. On the other hand \(f(0,y)=y\) has derivative \(1\).

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Review the concept: Partial derivative

The partial derivative of a function \(f(x,y)\) with respect to \(x\) at a point \((a,b)\) is the ordinary derivative of the one-variable function obtained by fixing \(y=b\) and letting only \(x\) vary.

\[f_x(a,b)=\lim_{h\to0}\frac{f(a+h,b)-f(a,b)}{h}\]

More practice problems: partial derivative

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