Exercise · ZW-REAL-INTEGRAL-BY-RESIDUES-010 · ★★★ Advanced

Compute \(\int_{-\infty}^{\infty}\frac{dx}{(x^{2}+1)^{3}}\).

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  • C. \(3\pi/8\)

Explanation

The pole \(i\) is triple; its residue is \(\tfrac12\,\tfrac{d^2}{dz^2}(z+i)^{-3}\) evaluated at \(i\), that is \(\tfrac{3}{16i}\). Then \(2\pi i\cdot\tfrac{3}{16i}=3\pi/8\).

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Review the concept: Real integral by residues

A method to compute \(\int_{-\infty}^{\infty} f(x)\,dx\) with \(f\) rational: close the real axis with a semicircle in the upper half-plane and apply the residue theorem.

\[\int_{-\infty}^{\infty} f(x)\,dx=2\pi i\sum_{\operatorname{Im}z_k>0}\operatorname{Res}(f,z_k)\]

More practice problems: real integral by residues

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