Exercise · ZW-ROLLES-THEOREM-006 · ★★☆ Intermediate

For \(f(x)=x^{3}-x\) on \([-1,1]\), which of these values satisfies \(f'(c)=0\) with \(c\in(-1,1)\)?

Choose one option.

Show answer
  • A. \(\frac{1}{\sqrt{3}}\)

Explanation

Since \(f'(x)=3x^{2}-1\), solving \(3c^{2}-1=0\) gives \(c=\pm\frac{1}{\sqrt{3}}\), both in \((-1,1)\). The positive value is the one listed.

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Review the concept: Rolle's theorem

If \(f\) is continuous on \([a,b]\), differentiable on \((a,b)\) and \(f(a)=f(b)\), there is at least one \(c\in(a,b)\) with \(f^{\prime}(c)=0\).

\[f(a)=f(b)\ \Rightarrow\ \exists\,c\in(a,b):\ f'(c)=0\]

More practice problems: rolle's theorem

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