Exercise · ZW-ROLLES-THEOREM-008 · ★★★ Advanced

Which of these cases is continuous with \(f(a)=f(b)\), but has no \(c\in(a,b)\) with \(f'(c)=0\)?

Choose one option.

Show answer
  • C. \(f(x)=|x|\) on \([-1,1]\)

Explanation

The function \(|x|\) is continuous with \(f(-1)=f(1)=1\), but it is not differentiable at \(0\), and elsewhere its derivative equals \(\pm 1\), never \(0\). The other cases either have a valid \(c\) or fail \(f(a)=f(b)\).

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Review the concept: Rolle's theorem

If \(f\) is continuous on \([a,b]\), differentiable on \((a,b)\) and \(f(a)=f(b)\), there is at least one \(c\in(a,b)\) with \(f^{\prime}(c)=0\).

\[f(a)=f(b)\ \Rightarrow\ \exists\,c\in(a,b):\ f'(c)=0\]

More practice problems: rolle's theorem

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