Exercise · ZW-SPECIAL-TRIG-LIMITS-001 · ★☆☆ Basic

Compute \(\lim_{x\to 0}\,\frac{\sin {3 x}}{x}\).

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  • A. \(3\)

Explanation

Write \(\dfrac{\sin 3x}{x}=3\cdot\dfrac{\sin 3x}{3x}\). Since \(\dfrac{\sin u}{u}\to1\) as \(u\to0\), the limit is \(3\cdot1=3\).

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Review the concept: Special trigonometric limits

Two basic limits in radians: \(\frac{\sin x}{x}\) tends to \(1\) and \(\frac{1-\cos x}{x}\) tends to \(0\) as \(x\) tends to \(0\).

\[\begin{gathered}\lim_{x\to0}\frac{\sin x}{x}=1\\ \lim_{x\to0}\frac{1-\cos x}{x}=0\end{gathered}\]

More practice problems: special trigonometric limits

ZW-SPECIAL-TRIG-LIMITS-002 →