Exercise · ZW-SPECIAL-TRIG-LIMITS-005 · ★★☆ Intermediate

Compute \(\lim_{x\to 0}\,\frac{\sin {2 x}}{\sin {3 x}}\).

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  • A. \(\frac{2}{3}\)

Explanation

Divide numerator and denominator by x: \(\dfrac{\sin 2x}{\sin 3x}=\dfrac{2\cdot\frac{\sin 2x}{2x}}{3\cdot\frac{\sin 3x}{3x}}\to\dfrac{2}{3}\).

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Review the concept: Special trigonometric limits

Two basic limits in radians: \(\frac{\sin x}{x}\) tends to \(1\) and \(\frac{1-\cos x}{x}\) tends to \(0\) as \(x\) tends to \(0\).

\[\begin{gathered}\lim_{x\to0}\frac{\sin x}{x}=1\\ \lim_{x\to0}\frac{1-\cos x}{x}=0\end{gathered}\]

More practice problems: special trigonometric limits

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