Exercise · ZW-SQUEEZE-THEOREM-004 · ★☆☆ Basic
What is \(\lim_{x\to 0} x\cos\!\left(\dfrac{1}{x}\right)\)?
Choose one option.
Show answer
- B. \(0\)
Exercise · ZW-SQUEEZE-THEOREM-004 · ★☆☆ Basic
Choose one option.
Since \(|\cos(1/x)|\le 1\), we have \(|x\cos(1/x)|\le |x|\), and \(|x|\to 0\). By the squeeze theorem, the limit is 0.
If \(g(x)\le f(x)\le h(x)\) near \(a\) and \(g\) and \(h\) both have limit \(L\) at \(a\), then \(f\) also has limit \(L\) at \(a\).