Exercise · ZW-SQUEEZE-THEOREM-007 · ★★☆ Intermediate

Let \(\lfloor y\rfloor\) be the greatest integer less than or equal to \(y\). What is \(\lim_{x\to 0^{+}} x\lfloor 1/x\rfloor\)?

Choose one option.

Show answer
  • C. \(1\)

Explanation

For \(x>0\), \(\dfrac{1}{x}-1<\lfloor 1/x\rfloor\le\dfrac{1}{x}\), so \(1-x<x\lfloor 1/x\rfloor\le 1\). Both bounds tend to 1, so the limit is 1.

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Review the concept: Squeeze theorem

If \(g(x)\le f(x)\le h(x)\) near \(a\) and \(g\) and \(h\) both have limit \(L\) at \(a\), then \(f\) also has limit \(L\) at \(a\).

\[g\le f\le h,\ \lim_{x\to a}g=\lim_{x\to a}h=L\ \Rightarrow\ \lim_{x\to a}f=L\]

More practice problems: squeeze theorem

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