Exercise · ZW-SUBSPACE-TOPOLOGY-010 · ★★★ Advanced
If \(A\subseteq B\subseteq X\), how do the topology \(A\) inherits from \(B\) and the one it inherits directly from \(X\) compare?
Choose one option.
A They coincide only if \(B\) is open in \(X\) B They coincide only if \(A\) is closed in \(B\) C They always coincide D They never coincide
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Explanation An open set of \(A\) as a subspace of \(B\) is \(A\cap(B\cap U)\) with \(U\) open in \(X\), and since \(A\subseteq B\) this is \(A\cap U\): the same as from \(X\). No hypothesis on \(B\) or \(A\) is needed.
The topology \(\mathcal{T}_A\) on a subset \(A\) of a topological space \((X,\mathcal{T})\) whose open sets are the intersections of \(A\) with the open sets \(U\) of \(X\).
\[\mathcal{T}_A=\{A\cap U:\ U\in\mathcal{T}\}\]
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