Exercise · ZW-SUPERPOSITION-PRINCIPLE-002 · ★☆☆ Basic
If \(\cos 2t\) and \(\sin 2t\) solve \(y''+4y=0\), which of these functions is a solution?
Choose one option.
Show answer
- D. \(3\cos 2t+\sin 2t\)
Exercise · ZW-SUPERPOSITION-PRINCIPLE-002 · ★☆☆ Basic
Choose one option.
Only \(3\cos 2t+\sin 2t\) is a linear combination of the two solutions. The product, the sum with \(1\) and \(\cos t+\sin t\) are not, and they do not make \(y''+4y\) vanish.
It states that if \(y_1\) and \(y_2\) are solutions of a linear homogeneous equation \(L[y]=0\), every linear combination of them with constants \(c_1,c_2\) is also a solution.
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