Exercise · ZW-SUPERPOSITION-PRINCIPLE-002 · ★☆☆ Basic

If \(\cos 2t\) and \(\sin 2t\) solve \(y''+4y=0\), which of these functions is a solution?

Choose one option.

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  • D. \(3\cos 2t+\sin 2t\)

Explanation

Only \(3\cos 2t+\sin 2t\) is a linear combination of the two solutions. The product, the sum with \(1\) and \(\cos t+\sin t\) are not, and they do not make \(y''+4y\) vanish.

Study Differential equations in ZWMath →

Review the concept: Superposition principle

It states that if \(y_1\) and \(y_2\) are solutions of a linear homogeneous equation \(L[y]=0\), every linear combination of them with constants \(c_1,c_2\) is also a solution.

\[L[c_1y_1+c_2y_2]=c_1L[y_1]+c_2L[y_2]=0\]

More practice problems: superposition principle

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