Exercise · ZW-SUPERPOSITION-PRINCIPLE-009 · ★★★ Advanced

\(y_1\) and \(y_2\) solve \(L[y]=g\) with \(g\neq0\). Which equation does \(y_1-y_2\) solve?

Choose one option.

Show answer
  • B. \(L[y]=0\)

Explanation

By linearity, \(L[y_1-y_2]=L[y_1]-L[y_2]=g-g=0\): the difference solves the homogeneous equation.

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Review the concept: Superposition principle

It states that if \(y_1\) and \(y_2\) are solutions of a linear homogeneous equation \(L[y]=0\), every linear combination of them with constants \(c_1,c_2\) is also a solution.

\[L[c_1y_1+c_2y_2]=c_1L[y_1]+c_2L[y_2]=0\]

More practice problems: superposition principle

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