Exercise · ZW-SUPERPOSITION-PRINCIPLE-007 · ★★☆ Intermediate
\(y=1\) solves \(y''+y=1\). Does \(y=2\) solve that same equation?
Choose one option.
Show answer
- A. No: the left side gives \(2\), not \(1\)
Explanation
Superposition only holds for homogeneous equations. With \(y=2\): \(y''+y=2\neq1\).
Review the concept: Superposition principle
It states that if \(y_1\) and \(y_2\) are solutions of a linear homogeneous equation \(L[y]=0\), every linear combination of them with constants \(c_1,c_2\) is also a solution.
\[L[c_1y_1+c_2y_2]=c_1L[y_1]+c_2L[y_2]=0\]
More practice problems: superposition principle
- ZW-SUPERPOSITION-PRINCIPLE-001 If e^t and e^-t solve y''-y=0, which of these functions also solves it?
- ZW-SUPERPOSITION-PRINCIPLE-002 If cos 2t and sin 2t solve y''+4y=0, which of these functions is a solution?
- ZW-SUPERPOSITION-PRINCIPLE-003 If e^2t and e^3t solve y''-5y'+6y=0, what is the value at t=0 of the solution e^2t+4e^3t?
- ZW-SUPERPOSITION-PRINCIPLE-004 Why is y=0 always a solution of a linear homogeneous equation?
- ZW-SUPERPOSITION-PRINCIPLE-005 If e^t and e^-2t solve y''+y'-2y=0, which value of c makes ce^t+e^-2t equal 3 at t=0?
- ZW-SUPERPOSITION-PRINCIPLE-006 If e^-t and e^-2t solve y''+3y'+2y=0, what is y'(0) for y=2e^-t+e^-2t?
- ZW-SUPERPOSITION-PRINCIPLE-008 y=-1/t solves y'=y^2, but y=-2/t does not. Why does superposition fail?
- ZW-SUPERPOSITION-PRINCIPLE-009 y_1 and y_2 solve L[y]=g with g≠0. Which equation does y_1-y_2 solve?
← ZW-SUPERPOSITION-PRINCIPLE-006 ZW-SUPERPOSITION-PRINCIPLE-008 →