Exercise · ZW-ZERO-AND-POLE-010 · ★★★ Advanced

\(f\) has a zero of order \(3\) and \(g\) a pole of order \(2\) at \(z_0\). What does \(fg\) have at \(z_0\)?

Choose one option.

Show answer
  • C. A zero of order \(1\)

Explanation

With \(f=(z-z_0)^3 f_1\) and \(g=\frac{g_1}{(z-z_0)^2}\), the product is \((z-z_0)\,f_1g_1\) with \(f_1g_1\neq0\) at \(z_0\): a zero of order \(3-2=1\).

Study Complex analysis in ZWMath →

Review the concept: Zero and pole

A zero of order \(m\) of a holomorphic function \(f\) is a point \(z_0\) where \(f\) vanishes with multiplicity \(m\), with holomorphic quotient \(g\); a pole of order \(m\) is a point where \(1/f\) has such a zero.

\[f(z)=(z-z_0)^m\,g(z),\qquad g(z_0)\neq 0\]

More practice problems: zero and pole

← ZW-ZERO-AND-POLE-009