Integration and series · Definition

Partition and Darboux sums

real analysisintegration

Before you start you need to know

It is the first step toward defining the area under a graph without appealing to intuition: it is trapped between rectangles lying below and above the function.

Definition

A partition \(P\) of \([a,b]\) splits it into subintervals of length \(\Delta x_i\); the lower sum \(L\) and upper sum \(U\) of Darboux use the infimum \(m_i\) and the supremum \(M_i\) of \(f\) on each one.

\[L(f,P)=\sum_{i=1}^{n} m_i\,\Delta x_i,\qquad U(f,P)=\sum_{i=1}^{n} M_i\,\Delta x_i\]

For a bounded function \(f\) on \([a,b]\), a partition is a list \(a=x_0<x_1<\dots<x_n=b\). On each subinterval \([x_{i-1},x_i]\) one takes \(m_i=\inf f\) and \(M_i=\sup f\), which exist by completeness of the reals; \(m_i\Delta x_i\) is the area of an inscribed rectangle and \(M_i\Delta x_i\) that of a circumscribed one. When \(f\) is continuous, the infimum and supremum are actually a minimum and a maximum; otherwise they exist only as bounds.

Guiding example: \(f(x)=x\) on \([0,1]\) with \(P=\{0,\tfrac12,1\}\) gives \(L=\tfrac14\) and \(U=\tfrac34\), with the area \(\tfrac12\) in between. If \(f\) increases, \(m_i\) sits at the left endpoint and \(M_i\) at the right; if it decreases, the reverse. A common mistake is to always use left and right endpoints without looking at how \(f\) behaves.

Always \(L(f,P)\le U(f,P)\). Moreover, a refinement \(Q\supseteq P\) tightens both sums: \(L(f,P)\le L(f,Q)\le U(f,Q)\le U(f,P)\). Merging two partitions into their common refinement shows that every lower sum is at most every upper sum, even if they come from different partitions.

That last property is what allows taking the supremum of the lower sums and the infimum of the upper sums, which is exactly what the Riemann integral does. For the Dirichlet function, by contrast, \(L=0\) and \(U=1\) for every partition: the sums never get closer.

Think about it

Why can refining a partition never worsen the lower sum?

When a subinterval is split in two, the infimum on each piece is at least the infimum on the original subinterval, so the sum does not decrease.

Can \(L(f,P)=U(f,P)\) hold for some partition with \(f\) non-constant?

Yes, if \(f\) is constant on each subinterval except perhaps at the partition points (for example a step function jumping at partition points); if \(f\) varies inside some subinterval, \(m_i<M_i\) and \(U-L>0\).

Exercises 10

What comes next

References

  • Stephen Abbott, Understanding Analysis, 2nd edition, Springer, 2015. §7.2
  • Walter Rudin, Principles of Mathematical Analysis, 3rd edition, McGraw-Hill, 1976. Cap. 6, Def. 6.1
  • Robert G. Bartle, Donald R. Sherbert, Introduction to Real Analysis, 4th edition, Wiley, 2011. §7.1