Exercise · ZW-ABSOLUTE-CONVERGENCE-009 · ★★★ Advanced
If \(\sum a_n\) converges absolutely, what happens to \(\sum a_n^2\)?
Choose one option.
Show answer
- A. It converges, because \(a_n^2\le|a_n|\) from some index on.
Exercise · ZW-ABSOLUTE-CONVERGENCE-009 · ★★★ Advanced
Choose one option.
Since \(a_n\to0\), there is \(N\) with \(|a_n|\le1\) for \(n\ge N\), so \(a_n^2\le|a_n|\). Compare with \(\sum|a_n|\). The sum of squares is not the square of the sum.
A series \(\sum a_n\) of real numbers converges absolutely when the series formed by the absolute values of its terms converges.