Exercise · ZW-ABSOLUTE-CONVERGENCE-009 · ★★★ Advanced

If \(\sum a_n\) converges absolutely, what happens to \(\sum a_n^2\)?

Choose one option.

Show answer
  • A. It converges, because \(a_n^2\le|a_n|\) from some index on.

Explanation

Since \(a_n\to0\), there is \(N\) with \(|a_n|\le1\) for \(n\ge N\), so \(a_n^2\le|a_n|\). Compare with \(\sum|a_n|\). The sum of squares is not the square of the sum.

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Review the concept: Absolute convergence

A series \(\sum a_n\) of real numbers converges absolutely when the series formed by the absolute values of its terms converges.

\[\sum_{n=1}^{\infty}|a_n|<\infty\]

More practice problems: absolute convergence

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