Exercise · ZW-ARCHIMEDEAN-PROPERTY-006 · ★★☆ Intermediate
What is the smallest natural \(n\) with \(\dfrac{n}{n+1}>0.999\)?
Choose one option.
Show answer
- B. \(1000\)
Explanation
\(\dfrac{n}{n+1}>0.999\) is equivalent to \(n>999\). With \(n=999\) we get \(0.999\), which is not greater.
Review the concept: Archimedean property
The property of \(\mathbb R\) by which, however small a positive number \(x\) is, some multiple of it by a natural \(n\in\mathbb N\) exceeds any real \(y\).
\[x>0,\ y\in\mathbb R\ \Longrightarrow\ \exists\, n\in\mathbb N:\ nx>y\]
More practice problems: archimedean property
- ZW-ARCHIMEDEAN-PROPERTY-001 What does the Archimedean property state?
- ZW-ARCHIMEDEAN-PROPERTY-002 What is the smallest natural n with tfrac1n<0.003?
- ZW-ARCHIMEDEAN-PROPERTY-003 By the Archimedean property, what is the infimum of \1/n: n∈mathbb N\?
- ZW-ARCHIMEDEAN-PROPERTY-004 If x=0.002 and y=5, what is the smallest natural n with nx>y?
- ZW-ARCHIMEDEAN-PROPERTY-005 Which statement is equivalent to the Archimedean property?
- ZW-ARCHIMEDEAN-PROPERTY-007 In an ordered field there is ε>0 with ε<tfrac1n for every natural n. Which property fails?
- ZW-ARCHIMEDEAN-PROPERTY-008 For x=tfrac37 and y=100, what is the smallest natural n with nx>y?
- ZW-ARCHIMEDEAN-PROPERTY-009 Which is the correct idea for proving the Archimedean property from the completeness axiom?