Exercise · ZW-COMPARISON-TEST-006 · ★★☆ Intermediate

Let \(a_n=\dfrac{2n+1}{n^3+4}\) and \(b_n=\dfrac1{n^2}\). Compute \(\displaystyle\lim_{n\to\infty}\frac{a_n}{b_n}\). (If the limit is finite and positive, both series behave alike.)

Choose one option.

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  • D. \(2\)

Explanation

\(\frac{a_n}{b_n}=\frac{n^2(2n+1)}{n^3+4}\to2\), finite and positive; since \(\sum b_n\) converges, so does \(\sum a_n\).

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Review the concept: Comparison test

A test that decides whether a series \(\sum a_n\) of nonnegative terms converges by comparing it with another series \(\sum b_n\) such that \(a_n\le b_n\).

\[0\le a_n\le b_n\ \Longrightarrow\ \Big(\sum b_n\text{ converges}\Rightarrow\sum a_n\text{ converges}\Big)\]

More practice problems: comparison test

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