Exercise · ZW-COMPLETENESS-AXIOM-009 · ★★★ Advanced

Let \(S\) be nonempty and bounded above, and \(M=\sup S\). Which statement is true?

Choose one option.

Show answer
  • C. For every \(\varepsilon>0\) there is \(s\in S\) with \(s>M-\varepsilon\)

Explanation

This is the characterization of the supremum: \(M-\varepsilon\) is not an upper bound. The others fail with \(S=(0,1)\) (where \(M=1\notin S\)) or with \(S=\{1\}\) (where \(s=M\)).

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Review the concept: Completeness axiom

The property that sets \(\mathbb R\) apart from \(\mathbb Q\): every nonempty set \(S\) of reals with an upper bound \(M\) has a supremum.

\[S\ne\varnothing,\ \exists M:\ s\le M\ \forall s\in S\ \Longrightarrow\ \sup S\in\mathbb R\]

More practice problems: completeness axiom

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