Exercise · ZW-COMPLEX-TRIGONOMETRIC-FUNCTIONS-010 · ★★★ Advanced

Is \(\sin z\) bounded on \(\mathbb{C}\)?

Choose one option.

Show answer
  • B. No: \(|\sin(iy)|=\sinh|y|\) grows without bound

Explanation

On the imaginary axis \(|\sin(iy)|=\sinh|y|\to\infty\). Periodicity holds only in the real direction and does not prevent growth; also \(\sin z\) is continuous on the whole plane.

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Review the concept: Complex trigonometric functions

The sine \(\sin z\) and cosine \(\cos z\) of a complex number \(z\) are the functions that extend the real ones through the complex exponential \(e^{iz}\).

\[\sin z=\frac{e^{iz}-e^{-iz}}{2i},\qquad \cos z=\frac{e^{iz}+e^{-iz}}{2}\]

More practice problems: complex trigonometric functions

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