Exercise · ZW-DIFFERENTIABILITY-SEVERAL-VARIABLES-003 · ★☆☆ Basic
Let \(f(x,y)=xe^{y}\). At \((2,0)\), with \(dx=0.05\) and \(dy=0.1\), what is \(df\)?
Choose one option.
A \(0.20\) B \(0.15\) C \(0.25\) D \(0.30\)
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Explanation \(f_x=e^{y}=1\) and \(f_y=xe^{y}=2\) at \((2,0)\); then \(df=1(0.05)+2(0.1)=0.25\). Swapping \(dx\) and \(dy\) gives \(0.20\).
A function \(f(x,y)\) is differentiable at a point \((a,b)\) if its graph has a tangent plane there: the error of the linear approximation is negligible compared with the distance to the point.
\[\lim_{(h,k)\to(0,0)}\frac{f(a+h,b+k)-f(a,b)-f_x(a,b)\,h-f_y(a,b)\,k}{\sqrt{h^2+k^2}}=0\]
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