Exercise · ZW-DIFFERENTIABILITY-SEVERAL-VARIABLES-007 · ★★☆ Intermediate
Let \(f(x,y)=\sqrt{x^2+y^2}\). Why is it not differentiable at the origin?
Choose one option.
A Because \(f_x(0,0)\) does not exist B Because it is not continuous at the origin C Because \(f(0,0)\neq0\) D Because its graph is a plane
Show answer A. Because \(f_x(0,0)\) does not exist
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Explanation The quotient \(\frac{f(h,0)-f(0,0)}{h}=\frac{|h|}{h}\) is \(1\) from the right and \(-1\) from the left, so \(f_x(0,0)\) does not exist (the graph is a cone with a vertex). It is continuous.
A function \(f(x,y)\) is differentiable at a point \((a,b)\) if its graph has a tangent plane there: the error of the linear approximation is negligible compared with the distance to the point.
\[\lim_{(h,k)\to(0,0)}\frac{f(a+h,b+k)-f(a,b)-f_x(a,b)\,h-f_y(a,b)\,k}{\sqrt{h^2+k^2}}=0\]
More practice problems: differentiability in several variables ZW-DIFFERENTIABILITY-SEVERAL-VARIABLES-001 Let f(x,y)=x^2y. Use the tangent plane at (1,2) to approximate f(1.1, 1.9).ZW-DIFFERENTIABILITY-SEVERAL-VARIABLES-002 For f(x,y)=x^2+3xy at (1,1), compute the differential df=f_x dx+f_y dy with dx=0.1, dy=-0.2.ZW-DIFFERENTIABILITY-SEVERAL-VARIABLES-003 Let f(x,y)=xe^y. At (2,0), with dx=0.05 and dy=0.1, what is df?ZW-DIFFERENTIABILITY-SEVERAL-VARIABLES-004 Find the linearization of f(x,y)=sin (xy) at the point (1,0).ZW-DIFFERENTIABILITY-SEVERAL-VARIABLES-005 Which condition guarantees that f is differentiable at (a,b)?ZW-DIFFERENTIABILITY-SEVERAL-VARIABLES-006 If f is differentiable at P, which statement is always true?ZW-DIFFERENTIABILITY-SEVERAL-VARIABLES-008 Which of these functions is differentiable on all of ℝ^2?ZW-DIFFERENTIABILITY-SEVERAL-VARIABLES-009 Let f(x,y)=(x^2y)/(x^2+y^2) with f(0,0)=0. Which statement is correct?