Exercise · ZW-DIFFERENTIABILITY-SEVERAL-VARIABLES-009 · ★★★ Advanced

Let \(f(x,y)=\dfrac{x^2y}{x^2+y^2}\) with \(f(0,0)=0\). Which statement is correct?

Choose one option.

Show answer
  • C. Its partials exist at the origin, but it is not differentiable

Explanation

Since \(f(h,0)=f(0,k)=0\), both partials equal \(0\) at the origin. But along \(h=k\) the error quotient equals \(\sqrt2/4\neq0\), so it is not differentiable. It is continuous: \(|f|\le|y|\).

Study Multivariable calculus in ZWMath →

Review the concept: Differentiability in several variables

A function \(f(x,y)\) is differentiable at a point \((a,b)\) if its graph has a tangent plane there: the error of the linear approximation is negligible compared with the distance to the point.

\[\lim_{(h,k)\to(0,0)}\frac{f(a+h,b+k)-f(a,b)-f_x(a,b)\,h-f_y(a,b)\,k}{\sqrt{h^2+k^2}}=0\]

More practice problems: differentiability in several variables

← ZW-DIFFERENTIABILITY-SEVERAL-VARIABLES-008 ZW-DIFFERENTIABILITY-SEVERAL-VARIABLES-010 →