Exercise · ZW-DIFFERENTIABILITY-SEVERAL-VARIABLES-009 · ★★★ Advanced
Let \(f(x,y)=\dfrac{x^2y}{x^2+y^2}\) with \(f(0,0)=0\). Which statement is correct?
Choose one option.
A It is not continuous at the origin B It is differentiable at the origin because its partials exist C Its partials exist at the origin, but it is not differentiable D \(f_x(0,0)\) does not exist
Show answer C. Its partials exist at the origin, but it is not differentiable
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Explanation Since \(f(h,0)=f(0,k)=0\), both partials equal \(0\) at the origin. But along \(h=k\) the error quotient equals \(\sqrt2/4\neq0\), so it is not differentiable . It is continuous: \(|f|\le|y|\).
A function \(f(x,y)\) is differentiable at a point \((a,b)\) if its graph has a tangent plane there: the error of the linear approximation is negligible compared with the distance to the point.
\[\lim_{(h,k)\to(0,0)}\frac{f(a+h,b+k)-f(a,b)-f_x(a,b)\,h-f_y(a,b)\,k}{\sqrt{h^2+k^2}}=0\]
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