Exercise · ZW-EIGENVALUE-AND-EIGENVECTOR-004 · ★☆☆ Basic

Let \(A=\begin{pmatrix}2&1\\1&2\end{pmatrix}\). Which of these vectors is an eigenvector of \(A\)?

Choose one option.

Show answer
  • B. \((1,-1)\)

Explanation

\(A(1,-1)=(2-1,\,1-2)=(1,-1)\), a multiple of itself (eigenvalue 1). The others give \((2,1)\), \((5,4)\) and \((4,5)\), which are not multiples of the original vector.

Study Linear algebra in ZWMath →

Review the concept: Eigenvalue and eigenvector

An eigenvector \(v\) of a square matrix \(A\) is a nonzero vector that \(A\) only stretches, shrinks or flips, without taking it off its line; the factor \(\lambda\) is its eigenvalue.

\[Av=\lambda v,\quad v\neq 0\]

More practice problems: eigenvalue and eigenvector

← ZW-EIGENVALUE-AND-EIGENVECTOR-003 ZW-EIGENVALUE-AND-EIGENVECTOR-005 →