Exercise · ZW-EIGENVALUE-AND-EIGENVECTOR-007 · ★★☆ Intermediate

How many real eigenvalues does the 90° rotation \(A=\begin{pmatrix}0&-1\\1&0\end{pmatrix}\) have?

Choose one option.

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  • D. None

Explanation

\(A\) turns every vector by 90°, so none stays on its own line: \(Av=\lambda v\) has no real solutions with \(v\neq0\). Its eigenvalues are \(\pm i\).

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Review the concept: Eigenvalue and eigenvector

An eigenvector \(v\) of a square matrix \(A\) is a nonzero vector that \(A\) only stretches, shrinks or flips, without taking it off its line; the factor \(\lambda\) is its eigenvalue.

\[Av=\lambda v,\quad v\neq 0\]

More practice problems: eigenvalue and eigenvector

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