Exercise · ZW-EIGENVALUE-AND-EIGENVECTOR-005 · ★★☆ Intermediate

Can the zero vector be an eigenvector?

Choose one option.

Show answer
  • B. No: by definition, an eigenvector is nonzero

Explanation

We require \(v\neq0\) because \(A0=\lambda0\) holds for every \(\lambda\); if it were allowed, every number would be an eigenvalue and the definition would say nothing.

Study Linear algebra in ZWMath →

Review the concept: Eigenvalue and eigenvector

An eigenvector \(v\) of a square matrix \(A\) is a nonzero vector that \(A\) only stretches, shrinks or flips, without taking it off its line; the factor \(\lambda\) is its eigenvalue.

\[Av=\lambda v,\quad v\neq 0\]

More practice problems: eigenvalue and eigenvector

← ZW-EIGENVALUE-AND-EIGENVECTOR-004 ZW-EIGENVALUE-AND-EIGENVECTOR-006 →