Exercise · ZW-EIGENVALUE-AND-EIGENVECTOR-005 · ★★☆ Intermediate
Can the zero vector be an eigenvector?
Choose one option.
Show answer
- B. No: by definition, an eigenvector is nonzero
Exercise · ZW-EIGENVALUE-AND-EIGENVECTOR-005 · ★★☆ Intermediate
Choose one option.
We require \(v\neq0\) because \(A0=\lambda0\) holds for every \(\lambda\); if it were allowed, every number would be an eigenvalue and the definition would say nothing.
An eigenvector \(v\) of a square matrix \(A\) is a nonzero vector that \(A\) only stretches, shrinks or flips, without taking it off its line; the factor \(\lambda\) is its eigenvalue.
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