Exercise · ZW-FUBINIS-THEOREM-003 · ★☆☆ Basic

Compute \(\iint_R e^{x+y}\,dA\) over \(R=[0,1]\times[0,1]\).

Choose one option.

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  • A. \((e-1)^2\)

Explanation

Since \(e^{x+y}=e^xe^y\), the result is \(\int_0^1e^x\,dx\cdot\int_0^1e^y\,dy=(e-1)^2\), not \(e^2-1\).

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Review the concept: Fubini's theorem

If \(f\) is continuous on a rectangle \(R=[a,b]\times[c,d]\), its double integral with respect to the area \(A\) is computed as an iterated integral, integrating in either order.

\[\iint_R f\,dA=\int_a^b\!\int_c^d f(x,y)\,dy\,dx=\int_c^d\!\int_a^b f(x,y)\,dx\,dy\]

More practice problems: fubini's theorem

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