Exercise · ZW-FUBINIS-THEOREM-005 · ★☆☆ Basic

Compute \(\iint_R \sin x\cos y\,dA\) over \(R=[0,\tfrac{\pi}{2}]\times[0,\tfrac{\pi}{2}]\).

Choose one option.

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  • B. \(1\)

Explanation

\(\int_0^{\pi/2}\sin x\,dx=1\) and \(\int_0^{\pi/2}\cos y\,dy=1\), so the integral equals \(1\).

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Review the concept: Fubini's theorem

If \(f\) is continuous on a rectangle \(R=[a,b]\times[c,d]\), its double integral with respect to the area \(A\) is computed as an iterated integral, integrating in either order.

\[\iint_R f\,dA=\int_a^b\!\int_c^d f(x,y)\,dy\,dx=\int_c^d\!\int_a^b f(x,y)\,dx\,dy\]

More practice problems: fubini's theorem

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