Exercise · ZW-FUBINIS-THEOREM-006 · ★★☆ Intermediate
Compute \(\iint_R 6xy^2\,dA\) over \(R=[0,1]\times[-1,1]\).
Choose one option.
A \(0\) B \(\tfrac43\) C \(2\) D \(4\)
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Explanation \(\int_0^1 6x\,dx=3\) and \(\int_{-1}^{1}y^2\,dy=\tfrac23\); the product is \(2\). It does not vanish: \(y^2\) is even.
If \(f\) is continuous on a rectangle \(R=[a,b]\times[c,d]\), its double integral with respect to the area \(A\) is computed as an iterated integral , integrating in either order.
\[\iint_R f\,dA=\int_a^b\!\int_c^d f(x,y)\,dy\,dx=\int_c^d\!\int_a^b f(x,y)\,dx\,dy\]
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