Exercise · ZW-LINES-AND-PLANES-IN-SPACE-010 · ★★★ Advanced
The lines \((1,0,0)+t\langle1,1,0\rangle\) and \((0,0,1)+s\langle0,1,2\rangle\) are not parallel. Do they meet?
Choose one option.
A Yes, at \((0,-1,0)\) B No: they are skew lines C Yes, at \((1,0,1)\) D Yes, at the origin
Show answer B. No: they are skew lines
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Explanation Equating coordinates: \(1+t=0\) gives \(t=-1\); \(t=s\) gives \(s=-1\); but the third, \(0=1+2s\), would require \(s=-\tfrac12\). The system is inconsistent, so they do not meet; being non-parallel, they are skew.
A line in space is determined by a point \(\mathbf r_0\) and a direction vector \(\mathbf d\); a plane, by a point \(\mathbf r_0\) and a normal vector \(\mathbf n\) perpendicular to it.
\[\begin{aligned}\mathbf r(t)&=\mathbf r_0+t\,\mathbf d\\\mathbf n\cdot(\mathbf r-\mathbf r_0)&=0\end{aligned}\]
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