Exercise · ZW-MEAN-VALUE-THEOREM-011 · ★☆☆ Basic

For \(f(x)=x^2\) on \([1,3]\), which point \(c\) does the mean value theorem guarantee?

Choose one option.

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  • B. \(c=2\)

Explanation

The chord slope is \(\frac{9-1}{3-1}=4\) and \(f'(c)=2c=4\) gives \(c=2\).

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Review the concept: Mean value theorem

If \(f\) is continuous on \([a,b]\) and differentiable on \((a,b)\), there is a \(c\in(a,b)\) such that the slope of the tangent at \(c\) equals the slope of the secant line joining \((a,f(a))\) and \((b,f(b))\).

\[f'(c)=\frac{f(b)-f(a)}{b-a}\]

More practice problems: mean value theorem

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