Exercise · ZW-MEAN-VALUE-THEOREM-011 · ★☆☆ Basic
For \(f(x)=x^2\) on \([1,3]\), which point \(c\) does the mean value theorem guarantee?
Choose one option.
Show answer
- B. \(c=2\)
Exercise · ZW-MEAN-VALUE-THEOREM-011 · ★☆☆ Basic
Choose one option.
The chord slope is \(\frac{9-1}{3-1}=4\) and \(f'(c)=2c=4\) gives \(c=2\).
If \(f\) is continuous on \([a,b]\) and differentiable on \((a,b)\), there is a \(c\in(a,b)\) such that the slope of the tangent at \(c\) equals the slope of the secant line joining \((a,f(a))\) and \((b,f(b))\).