Exercise · ZW-MEAN-VALUE-THEOREM-012 · ★☆☆ Basic

For \(f(x)=x^3\) on \([0,2]\), which \(c\in(0,2)\) satisfies the conclusion of the theorem?

Choose one option.

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  • D. \(c=\tfrac{2}{\sqrt3}\)

Explanation

The chord slope is \(\frac{8-0}{2}=4\). From \(3c^2=4\) and \(c>0\) we get \(c=\frac{2}{\sqrt3}\approx1.155\).

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Review the concept: Mean value theorem

If \(f\) is continuous on \([a,b]\) and differentiable on \((a,b)\), there is a \(c\in(a,b)\) such that the slope of the tangent at \(c\) equals the slope of the secant line joining \((a,f(a))\) and \((b,f(b))\).

\[f'(c)=\frac{f(b)-f(a)}{b-a}\]

More practice problems: mean value theorem

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