Exercise · ZW-ORDERED-FIELD-002 · ★☆☆ Basic
Which of these sets, with the usual operations and order, is not an ordered field?
Choose one option.
Show answer
- C. \(\mathbb Z\)
Explanation
\(\mathbb Z\) is not a field: \(2\) has no multiplicative inverse in \(\mathbb Z\).
Review the concept: Ordered field
An ordered field is a field \(F\) with a total order \(<\) compatible with addition and with multiplication by positive elements.
\[a0\Rightarrow ac
More practice problems: ordered field
- ZW-ORDERED-FIELD-001 If a<b and c<0 in an ordered field, what holds?
- ZW-ORDERED-FIELD-003 Which statement is true in every ordered field F?
- ZW-ORDERED-FIELD-004 If a<b in an ordered field, which inequality follows?
- ZW-ORDERED-FIELD-005 Multiply the inequality -3<2 by -4. What results?
- ZW-ORDERED-FIELD-006 If 0<a<b, which is true?
- ZW-ORDERED-FIELD-007 For a,b in an ordered field, how many of a<b, a=b, a>b are true?
- ZW-ORDERED-FIELD-008 If 0<a<b in an ordered field, how do a+b and 2a compare?
- ZW-ORDERED-FIELD-009 Why can the finite field mathbb Z/p (p prime) not be made an ordered field?