Exercise · ZW-RESIDUE-005 · ★★☆ Intermediate

What is the residue of \(\frac{e^z}{(z-1)^2}\) at \(z=1\)?

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  • A. \(e\)

Explanation

With \(w=z-1\), \(\frac{e^z}{(z-1)^2}=\frac{e\,e^{w}}{w^2}=\frac{e}{w^2}+\frac{e}{w}+\cdots\); the coefficient of \(w^{-1}\) is \(e\).

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Review the concept: Residue

The residue of a function \(f\) at an isolated singularity \(z_0\) is the coefficient \(a_{-1}\) of \((z-z_0)^{-1}\) in its Laurent series on a punctured disc of radius \(r\).

\[\operatorname{Res}(f,z_0)=a_{-1}=\frac{1}{2\pi i}\oint_{|z-z_0|=r/2}f(z)\,dz\]

More practice problems: residue

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