Exercise · ZW-RESIDUE-008 · ★★★ Advanced

What is the residue of \(\frac{1}{z^3(z-2)}\) at \(z=0\)?

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  • C. \(-\frac18\)

Explanation

Near \(0\), \(\frac{1}{z-2}=-\frac12\left(1+\frac z2+\frac{z^2}{4}+\cdots\right)\). Dividing by \(z^3\) puts the \(z^2\) term at \(z^{-1}\): the coefficient is \(-\frac12\cdot\frac14=-\frac18\).

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Review the concept: Residue

The residue of a function \(f\) at an isolated singularity \(z_0\) is the coefficient \(a_{-1}\) of \((z-z_0)^{-1}\) in its Laurent series on a punctured disc of radius \(r\).

\[\operatorname{Res}(f,z_0)=a_{-1}=\frac{1}{2\pi i}\oint_{|z-z_0|=r/2}f(z)\,dz\]

More practice problems: residue

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