Exercise · ZW-RESIDUE-009 · ★★★ Advanced

Compute \(\displaystyle\oint_{|z|=1}\frac{e^z}{z^3}\,dz\), with the circle traversed once counterclockwise.

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  • A. \(\pi i\)

Explanation

The integral equals \(2\pi i\) times the residue of \(\frac{e^z}{z^3}\) at \(0\), which is the coefficient of \(z^2\) in \(e^z\): \(\frac12\). The result is \(2\pi i\cdot\frac12=\pi i\).

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Review the concept: Residue

The residue of a function \(f\) at an isolated singularity \(z_0\) is the coefficient \(a_{-1}\) of \((z-z_0)^{-1}\) in its Laurent series on a punctured disc of radius \(r\).

\[\operatorname{Res}(f,z_0)=a_{-1}=\frac{1}{2\pi i}\oint_{|z-z_0|=r/2}f(z)\,dz\]

More practice problems: residue

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