Exercise · ZW-RESIDUE-007 · ★★☆ Intermediate

What is the residue of \(\frac{1}{\sin z}\) at \(z=\pi\)?

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  • B. \(-1\)

Explanation

At a simple pole, the residue of \(\frac{1}{h}\) is \(\frac{1}{h'(z_0)}\). Here \(h'(\pi)=\cos\pi=-1\), so the residue is \(-1\).

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Review the concept: Residue

The residue of a function \(f\) at an isolated singularity \(z_0\) is the coefficient \(a_{-1}\) of \((z-z_0)^{-1}\) in its Laurent series on a punctured disc of radius \(r\).

\[\operatorname{Res}(f,z_0)=a_{-1}=\frac{1}{2\pi i}\oint_{|z-z_0|=r/2}f(z)\,dz\]

More practice problems: residue

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