Exercise · ZW-RIEMANN-INTEGRAL-010 · ★★★ Advanced

If \(f\) is integrable on \([0,2]\) and \(1\le f(x)\le3\), what is the tightest interval guaranteed to contain \(\int_0^2 f\)?

Choose one option.

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  • A. \([2,6]\)

Explanation

Every lower sum is \(\ge1\cdot2\) and every upper sum is \(\le3\cdot2\), so \(2\le\int_0^2 f\le6\). Bounds like \([1,3]\) forget to multiply by the length \(b-a=2\).

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Review the concept: Riemann integral

A bounded function \(f\) on \([a,b]\) is integrable if the supremum \(L(f)\) of its lower sums and the infimum \(U(f)\) of its upper sums, over partitions \(P\), coincide; that common value is its integral.

\[L(f)=\sup_P L(f,P)=\inf_P U(f,P)=U(f)=\int_a^b f(x)\,dx\]

More practice problems: riemann integral

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