Exercise · ZW-ROLLES-THEOREM-010 · ★★☆ Intermediate

For \(f(x)=x^{2}-6x+5\) on \([1,5]\), which value of \(c\in(1,5)\) satisfies \(f'(c)=0\)?

Choose one option.

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  • A. \(3\)

Explanation

We have \(f(1)=f(5)=0\). Since \(f'(x)=2x-6\), solving \(2c-6=0\) gives \(c=3\), which lies in \((1,5)\). The endpoints do not count because the interval is open.

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Review the concept: Rolle's theorem

If \(f\) is continuous on \([a,b]\), differentiable on \((a,b)\) and \(f(a)=f(b)\), there is at least one \(c\in(a,b)\) with \(f^{\prime}(c)=0\).

\[f(a)=f(b)\ \Rightarrow\ \exists\,c\in(a,b):\ f'(c)=0\]

More practice problems: rolle's theorem

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