Exercise · ZW-SPECIAL-TRIG-LIMITS-010 · ★★☆ Intermediate
Compute \(\lim_{x\to 0}\,\frac{\tan {2x}}{\sin {5x}}\).
Choose one option.
Show answer
- D. \(\frac{2}{5}\)
Exercise · ZW-SPECIAL-TRIG-LIMITS-010 · ★★☆ Intermediate
Choose one option.
Since \(\tan 2x=\dfrac{\sin 2x}{\cos 2x}\), the quotient is \(\dfrac{\sin 2x}{\sin 5x}\cdot\dfrac{1}{\cos 2x}\to\dfrac{2}{5}\cdot1\cdot1=\dfrac{2}{5}\).
Two basic limits in radians: \(\frac{\sin x}{x}\) tends to \(1\) and \(\frac{1-\cos x}{x}\) tends to \(0\) as \(x\) tends to \(0\).