Exercise · ZW-UNIQUENESS-OF-LIMITS-006 · ★★☆ Intermediate
If \(a_n\to L\) and \(a_n\to M\), then \(a_n-a_n=0\) converges to \(L-M\) and also to \(0\). What follows?
Choose one option.
Show answer
- C. \(L-M=0\)
Exercise · ZW-UNIQUENESS-OF-LIMITS-006 · ★★☆ Intermediate
Choose one option.
The constant sequence \(0\) converges to \(0\); comparing with \(L-M\) gives \(L-M=0\), i.e. \(L=M\).
Uniqueness of limits says that a sequence \((a_n)\) cannot converge to two different numbers \(L\) and \(M\); that is why it makes sense to speak of “the” limit.