Exercise · ZW-UNIQUENESS-OF-LIMITS-006 · ★★☆ Intermediate

If \(a_n\to L\) and \(a_n\to M\), then \(a_n-a_n=0\) converges to \(L-M\) and also to \(0\). What follows?

Choose one option.

Show answer
  • C. \(L-M=0\)

Explanation

The constant sequence \(0\) converges to \(0\); comparing with \(L-M\) gives \(L-M=0\), i.e. \(L=M\).

Study Real analysis in ZWMath →

Review the concept: Uniqueness of limits

Uniqueness of limits says that a sequence \((a_n)\) cannot converge to two different numbers \(L\) and \(M\); that is why it makes sense to speak of “the” limit.

\[a_n\to L,\ a_n\to M\ \Rightarrow\ L=M\]

More practice problems: uniqueness of limits

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