Exercise · ZW-COMPLEX-CONTINUITY-001 · ★☆☆ Basic

At which points is \(f(z)=\dfrac{1}{z-2}\) continuous?

Choose one option.

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  • C. On \(\mathbb{C}\setminus\{2\}\)

Explanation

It is a quotient of continuous functions whose denominator vanishes only at \(z=2\), outside the domain; it is continuous on its whole domain \(\mathbb{C}\setminus\{2\}\).

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Review the concept: Complex continuity

A function \(f\) is continuous at a point \(z_0\) of its domain if \(f(z)\) tends to the value \(f(z_0)\) as \(z\) tends to \(z_0\); it is continuous if it is so at every point of its domain.

\[\lim_{z\to z_0}f(z)=f(z_0)\]

More practice problems: complex continuity

ZW-COMPLEX-CONTINUITY-002 →