Exercise · ZW-COMPLEX-CONTINUITY-003 · ★☆☆ Basic
Let \(f(z)=\dfrac{z^2-4}{z-2}\) for \(z\neq 2\) and \(f(2)=c\). Which \(c\) makes it continuous at \(2\)?
Choose one option.
Show answer
- D. \(4\)
Exercise · ZW-COMPLEX-CONTINUITY-003 · ★☆☆ Basic
Choose one option.
For \(z\neq 2\), \(f(z)=z+2\), whose limit at \(2\) is \(4\); continuity requires \(c=4\).
A function \(f\) is continuous at a point \(z_0\) of its domain if \(f(z)\) tends to the value \(f(z_0)\) as \(z\) tends to \(z_0\); it is continuous if it is so at every point of its domain.