Exercise · ZW-COMPLEX-CONTINUITY-006 · ★★☆ Intermediate

Let \(f(z)=z^2\) and \(g(w)=\dfrac{1}{w-4}\). At which points is \(g(f(z))\) continuous?

Choose one option.

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  • B. On \(\mathbb{C}\setminus\{2,-2\}\)

Explanation

The composition \(1/(z^2-4)\) is continuous where \(f(z)\) lies in the domain of \(g\), i.e. \(z^2\neq 4\), so \(z\neq\pm 2\).

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Review the concept: Complex continuity

A function \(f\) is continuous at a point \(z_0\) of its domain if \(f(z)\) tends to the value \(f(z_0)\) as \(z\) tends to \(z_0\); it is continuous if it is so at every point of its domain.

\[\lim_{z\to z_0}f(z)=f(z_0)\]

More practice problems: complex continuity

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