Exercise · ZW-COMPLEX-CONTINUITY-008 · ★★☆ Intermediate

Compute \(\lim_{z\to 1+i}\big(\operatorname{Re}(z^2)+\operatorname{Im}(\bar z)\big)\).

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  • A. \(-1\)

Explanation

The function is continuous on all of \(\mathbb{C}\), so substitute: \(\operatorname{Re}((1+i)^2)=\operatorname{Re}(2i)=0\) and \(\operatorname{Im}(1-i)=-1\); the value is \(-1\).

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Review the concept: Complex continuity

A function \(f\) is continuous at a point \(z_0\) of its domain if \(f(z)\) tends to the value \(f(z_0)\) as \(z\) tends to \(z_0\); it is continuous if it is so at every point of its domain.

\[\lim_{z\to z_0}f(z)=f(z_0)\]

More practice problems: complex continuity

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