Exercise · ZW-COMPLEX-CONTINUITY-005 · ★☆☆ Basic
Let \(f(z)=\dfrac{z^2}{|z|}\) for \(z\neq 0\) and \(f(0)=0\). Is it continuous at \(0\)?
Choose one option.
Show answer
- C. Yes, because \(|f(z)|=|z|\to 0=f(0)\)
Exercise · ZW-COMPLEX-CONTINUITY-005 · ★☆☆ Basic
Choose one option.
The modulus of \(f(z)\) is \(|z|\), which tends to \(0\); hence \(\lim_{z\to 0}f(z)=0=f(0)\) and \(f\) is continuous at \(0\).
A function \(f\) is continuous at a point \(z_0\) of its domain if \(f(z)\) tends to the value \(f(z_0)\) as \(z\) tends to \(z_0\); it is continuous if it is so at every point of its domain.