Exercise · ZW-COMPLEX-CONTINUITY-009 · ★★★ Advanced

If \(f\) is continuous on the closed disk \(|z|\le 1\), which claim is certain?

Choose one option.

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  • C. \(|f|\) attains a maximum at some point of the disk

Explanation

The closed disk is closed and bounded, and \(|f|\) is continuous and real-valued: it attains its maximum (Weierstrass theorem). Continuity does not imply holomorphy.

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Review the concept: Complex continuity

A function \(f\) is continuous at a point \(z_0\) of its domain if \(f(z)\) tends to the value \(f(z_0)\) as \(z\) tends to \(z_0\); it is continuous if it is so at every point of its domain.

\[\lim_{z\to z_0}f(z)=f(z_0)\]

More practice problems: complex continuity

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