Exercise · ZW-RELATED-RATES-001 · ★☆☆ Basic

The radius of a circle grows at 2 cm/s. How fast is the area growing when \(r = 5\) cm?

Choose one option.

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  • A. \(20 \pi\)

Explanation

From \(A=\pi r^{2}\) we get \(\dfrac{dA}{dt}=2\pi r\,\dfrac{dr}{dt}=2\pi(5)(2)=20 \pi\) cm²/s.

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Review the concept: Related rates

In a related rates problem several quantities change with time \(t\) and are linked by an equation. The equation is differentiated with respect to \(t\) (chain rule) and the known values are substituted.

\[A=\pi r^{2}\ \Rightarrow\ \frac{dA}{dt}=2\pi r\,\frac{dr}{dt}\]

More practice problems: related rates

ZW-RELATED-RATES-002 →