Exercise · ZW-RELATED-RATES-002 · ★★☆ Intermediate
The radius of a sphere grows at \(\frac{1}{2}\) cm/s. How fast is the volume growing when \(r = 3\) cm?
Choose one option.
Show answer
- D. \(18 \pi\)
Exercise · ZW-RELATED-RATES-002 · ★★☆ Intermediate
Choose one option.
From \(V=\dfrac{4}{3}\pi r^{3}\) we get \(\dfrac{dV}{dt}=4\pi r^{2}\dfrac{dr}{dt}=4\pi(3)^{2}\cdot\frac{1}{2}=18 \pi\) cm³/s.
In a related rates problem several quantities change with time \(t\) and are linked by an equation. The equation is differentiated with respect to \(t\) (chain rule) and the known values are substituted.