Exercise · ZW-RELATED-RATES-008 · ★★☆ Intermediate

The radius of a sphere is \(2\) cm and grows at \(\frac{1}{2}\) cm/s. How fast is its surface area growing? (in cm²/s)

Choose one option.

Show answer
  • B. \(8\pi\)

Explanation

With \(S=4\pi r^{2}\) we get \(\dfrac{dS}{dt}=8\pi r\,\dfrac{dr}{dt}=8\pi(2)\frac{1}{2}=8\pi\) cm²/s.

Study Calculus in ZWMath →

Review the concept: Related rates

In a related rates problem several quantities change with time \(t\) and are linked by an equation. The equation is differentiated with respect to \(t\) (chain rule) and the known values are substituted.

\[A=\pi r^{2}\ \Rightarrow\ \frac{dA}{dt}=2\pi r\,\frac{dr}{dt}\]

More practice problems: related rates

← ZW-RELATED-RATES-007 ZW-RELATED-RATES-009 →