Exercise · ZW-RELATED-RATES-008 · ★★☆ Intermediate
The radius of a sphere is \(2\) cm and grows at \(\frac{1}{2}\) cm/s. How fast is its surface area growing? (in cm²/s)
Choose one option.
Show answer
- B. \(8\pi\)
Exercise · ZW-RELATED-RATES-008 · ★★☆ Intermediate
Choose one option.
With \(S=4\pi r^{2}\) we get \(\dfrac{dS}{dt}=8\pi r\,\dfrac{dr}{dt}=8\pi(2)\frac{1}{2}=8\pi\) cm²/s.
In a related rates problem several quantities change with time \(t\) and are linked by an equation. The equation is differentiated with respect to \(t\) (chain rule) and the known values are substituted.