Exercise · ZW-RELATED-RATES-004 · ★☆☆ Basic

The edge of a cube grows at 1 cm/s. How fast is the volume growing when the edge is 4 cm?

Choose one option.

Show answer
  • B. \(48\)

Explanation

From \(V=s^{3}\) we get \(\dfrac{dV}{dt}=3s^{2}\dfrac{ds}{dt}=3(4)^{2}(1)=48\) cm³/s.

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Review the concept: Related rates

In a related rates problem several quantities change with time \(t\) and are linked by an equation. The equation is differentiated with respect to \(t\) (chain rule) and the known values are substituted.

\[A=\pi r^{2}\ \Rightarrow\ \frac{dA}{dt}=2\pi r\,\frac{dr}{dt}\]

More practice problems: related rates

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